AVL Trees: Rotations, Insertion, Deletion with C++ Example
โก Smart Summary
AVL Trees are self-balancing binary search trees where the height difference between the left and right subtrees of every node stays within -1, 0, or +1, guaranteeing O(log n) search performance.

What are AVL Trees?
AVL Trees are binary search trees in which the height difference between the left and right subtree of every node is -1, 0, or +1. They are self-balancing BSTs that maintain logarithmic search time, named after inventors Adelson-Velsky and Landis (AVL).
How does AVL Tree work?
To understand why AVL Trees exist, look at what goes wrong with a plain Binary Search Tree. Consider these keys inserted in the given order:
AVL tree visualization
The tree grows linearly when keys arrive in increasing order, degenerating search to O(n). That defeats the purpose of a BST โ only a balanced tree keeps search logarithmic. Now look at the same keys inserted in a different order.
Same keys, different insertion order produces a shallower shape, so every search runs in O(log n). AVL Trees enforce that shape by watching the height on every insertion and correcting imbalance without breaking BST ordering.
Balance Factor in AVL Trees
The balance factor (BF) tracks each node’s height so the tree can self-balance on the fly.
Properties of Balance Factor
Balance factor AVL tree
- The balance factor is the difference between the height of the left subtree and the height of the right subtree.
Balance factor(node) = height(node->left) โ height(node->right)- The only allowed values are โ1, 0, and +1.
- A value of โ1 means the right subtree contains one extra level โ the node is right-heavy.
- A value of +1 means the left subtree contains one extra level โ the node is left-heavy.
- A value of 0 means both sides have equal height โ the node is perfectly balanced.
AVL Rotations
Rotations run whenever an insertion or deletion breaks the balance factor rule. The four cases are LL, RR, LR, and RL.
Left โ Left Rotation
This rotation is performed when a new node is inserted at the left child of the left subtree.
AVL Tree Left โ Left Rotation
A single right rotation is performed. This case fires when a node has BF +2 and its left child has BF +1.
Right โ Right Rotation
This rotation is performed when a new node is inserted at the right child of the right subtree.
A single left rotation is performed. This case fires when a node has BF โ2 and its right child has BF โ1.
Right โ Left Rotation
This rotation is performed when a new node is inserted at the left child of the right subtree.
Fires when BF(node) = โ2 and BF(right-child) = +1. Right-rotate the right child, then left-rotate the node.
Left โ Right Rotation
This rotation is performed when a new node is inserted at the right child of the left subtree.
Fires when BF(node) = +2 and BF(left-child) = โ1. Left-rotate the left child, then right-rotate the node.
Insertion in AVL Trees
Insertion is almost identical to a plain BST insert. After every insert, the tree walks up and re-balances. Insert runs in O(log n) worst-case time.
AVL tree insertion implementation
Step 1: Insert the node using the standard BST algorithm. In the example above, insert 160.
Step 2: Update the balance factor of every ancestor along the insertion path.
Step 3: If any ancestor violates the balance factor range, perform the matching rotation. In the example, node 350’s balance factor is violated, so an LL rotation restores balance.
- If
BF(node) = +2andBF(left-child) = +1, perform LL rotation. - If
BF(node) = โ2andBF(right-child) = โ1, perform RR rotation. - If
BF(node) = โ2andBF(right-child) = +1, perform RL rotation. - If
BF(node) = +2andBF(left-child) = โ1, perform LR rotation.
Deletion in AVL Trees
Deletion follows the same logic as a plain BST and re-balances afterwards.
Step 1: Find the element in the tree.
Step 2: Delete the node using standard BST deletion.
Step 3: Two cases are possible.
Case 1: Deleting from the right subtree.
- 1A. If
BF(node) = +2andBF(left-child) = +1, perform LL rotation. - 1B. If
BF(node) = +2andBF(left-child) = โ1, perform LR rotation. - 1C. If
BF(node) = +2andBF(left-child) = 0, perform LL rotation.
Case 2: Deleting from the left subtree.
- 2A. If
BF(node) = โ2andBF(right-child) = โ1, perform RR rotation. - 2B. If
BF(node) = โ2andBF(right-child) = +1, perform RL rotation. - 2C. If
BF(node) = โ2andBF(right-child) = 0, perform RR rotation.
C++ Example of AVL Trees
Below is a C++ program implementing AVL Trees:
#include <iostream> #include <queue> #include <unordered_map> using namespace std; struct node { struct node *left; int data; int height; struct node *right; }; class AVL { public: struct node *root; AVL() { this->root = NULL; } int calheight(struct node *p) { if (p->left && p->right) { if (p->left->height < p->right->height) return p->right->height + 1; else return p->left->height + 1; } else if (p->left && p->right == NULL) { return p->left->height + 1; } else if (p->left == NULL && p->right) { return p->right->height + 1; } return 0; } int bf(struct node *n) { if (n->left && n->right) return n->left->height - n->right->height; else if (n->left && n->right == NULL) return n->left->height; else if (n->left == NULL && n->right) return -n->right->height; return 0; } struct node *llrotation(struct node *n) { struct node *p = n; struct node *tp = p->left; p->left = tp->right; tp->right = p; return tp; } struct node *rrrotation(struct node *n) { struct node *p = n; struct node *tp = p->right; p->right = tp->left; tp->left = p; return tp; } struct node *rlrotation(struct node *n) { struct node *p = n; struct node *tp = p->right; struct node *tp2 = p->right->left; p->right = tp2->left; tp->left = tp2->right; tp2->left = p; tp2->right = tp; return tp2; } struct node *lrrotation(struct node *n) { struct node *p = n; struct node *tp = p->left; struct node *tp2 = p->left->right; p->left = tp2->right; tp->right = tp2->left; tp2->right = p; tp2->left = tp; return tp2; } struct node *insert(struct node *r, int data) { if (r == NULL) { r = new struct node; r->data = data; r->left = r->right = NULL; r->height = 1; return r; } if (data < r->data) r->left = insert(r->left, data); else r->right = insert(r->right, data); r->height = calheight(r); if (bf(r) == 2 && bf(r->left) == 1) r = llrotation(r); else if (bf(r) == -2 && bf(r->right) == -1) r = rrrotation(r); else if (bf(r) == -2 && bf(r->right) == 1) r = rlrotation(r); else if (bf(r) == 2 && bf(r->left) == -1) r = lrrotation(r); return r; } void levelorder_newline() { if (this->root == NULL) { cout << "\nEmpty tree\n"; return; } levelorder_newline(this->root); } void levelorder_newline(struct node *v) { queue<struct node *> q; struct node *cur; q.push(v); q.push(NULL); while (!q.empty()) { cur = q.front(); q.pop(); if (cur == NULL && q.size() != 0) { cout << "\n"; q.push(NULL); continue; } if (cur != NULL) { cout << " " << cur->data; if (cur->left != NULL) q.push(cur->left); if (cur->right != NULL) q.push(cur->right); } } } struct node *deleteNode(struct node *p, int data) { if (p->left == NULL && p->right == NULL) { if (p == this->root) this->root = NULL; delete p; return NULL; } struct node *q; if (p->data < data) p->right = deleteNode(p->right, data); else if (p->data > data) p->left = deleteNode(p->left, data); else { if (p->left != NULL) { q = inpre(p->left); p->data = q->data; p->left = deleteNode(p->left, q->data); } else { q = insuc(p->right); p->data = q->data; p->right = deleteNode(p->right, q->data); } } if (bf(p) == 2 && bf(p->left) == 1) p = llrotation(p); else if (bf(p) == 2 && bf(p->left) == -1) p = lrrotation(p); else if (bf(p) == 2 && bf(p->left) == 0) p = llrotation(p); else if (bf(p) == -2 && bf(p->right) == -1) p = rrrotation(p); else if (bf(p) == -2 && bf(p->right) == 1) p = rlrotation(p); else if (bf(p) == -2 && bf(p->right) == 0) p = rrrotation(p); return p; } struct node *inpre(struct node *p) { while (p->right != NULL) p = p->right; return p; } struct node *insuc(struct node *p) { while (p->left != NULL) p = p->left; return p; } ~AVL() {} }; int main() { AVL b; int c, x; do { cout << "\n1.Display levelorder on newline"; cout << "\n2.Insert"; cout << "\n3.Delete\n"; cout << "\n0.Exit\n"; cout << "\nChoice: "; cin >> c; switch (c) { case 1: b.levelorder_newline(); break; case 2: cout << "\nEnter no. "; cin >> x; b.root = b.insert(b.root, x); break; case 3: cout << "\nWhat to delete? "; cin >> x; b.root = b.deleteNode(b.root, x); break; case 0: break; } } while (c != 0); }
Running example of the code above:
- Copy the code above and save it in a file named
avl.cpp. - Compile the code:
g++ avl.cpp -o run
- Run the code.
./run
Advantages of AVL Trees
- The height of the AVL Tree is always balanced and never grows beyond log N.
- Search is faster than a plain Binary Search Tree because the tree cannot degenerate.
- Self-balancing is automatic โ no rebuild step is required.
- Deterministic performance suits real-time systems and in-memory indexes.











