Árboles AVL: rotaciones, inserción, eliminación con C++ Ejemplo

Por: sarah chen sarah chen
Hours Actualizado

⚡ Resumen inteligente

AVL Trees are self-balancing binary search trees where the height difference between the left and right subtrees of every node stays within -1, 0, or +1, guaranteeing O(log n) search performance.

  • 🌲 Definición: A binary search tree in which the balance factor of every node lies in {-1, 0, +1}, named after inventors Adelson-Velsky and Landis.
  • 🇧🇷 Factor de equilibrio: Computed as height(left) − height(right); values outside {-1, 0, +1} trigger a rotation to restore balance.
  • 🔄 Rotaciones: Four cases — LL, RR, LR, and RL — realign nodes after unbalanced insertions or deletions to keep the tree logarithmic in height.
  • ➕ Inserción: Standard BST insert followed by an upward walk that recomputes balance factors and performs at most one single or double rotation.
  • ➖ Supresión: Same as BST deletion but may cascade multiple rotations up the tree because subtree height can shrink at every ancestor.
  • 🚀 Aplicaciones: Databases, in-memory indexes, filesystem metadata, and AI search structures use AVL Trees for fast ordered lookups.
Descubre más

Árboles AVL

¿Qué son los árboles AVL?

Árboles AVL are binary search trees in which the height difference between the left and right subtree of every node is -1, 0, or +1. They are self-balancing BSTs that maintain logarithmic search time, named after inventors Adelson-Velsky and Landis (AVL).

¿Cómo funciona el árbol AVL?

To understand why AVL Trees exist, look at what goes wrong with a plain Árbol de búsqueda binaria. Consider these keys inserted in the given order:

Trabajo de árbol AVL

Visualización del árbol AVL

The tree grows linearly when keys arrive in increasing order, degenerating search to O(n). That defeats the purpose of a BST — only a balanced tree keeps search logarithmic. Now look at the same keys inserted in a different order.

Trabajo de árbol AVL

Same keys, different insertion order produces a shallower shape, so every search runs in O(log n). AVL Trees enforce that shape by watching the height on every insertion and correcting imbalance without breaking BST ordering.

Factor de equilibrio en árboles AVL

The balance factor (BF) tracks each node’s height so the tree can self-balance on the fly.

Propiedades del factor de equilibrio

Factor de equilibrio en árboles AVL

Factor de equilibrio árbol AVL

  • The balance factor is the difference between the height of the left subtree and the height of the right subtree.
  • Balance factor(node) = height(node->left) − height(node->right)
  • The only allowed values are −1, 0, and +1.
  • A value of −1 means the right subtree contains one extra level — the node is right-heavy.
  • A value of +1 means the left subtree contains one extra level — the node is left-heavy.
  • A value of 0 means both sides have equal height — the node is perfectly balanced.

Rotaciones AVL

Rotations run whenever an insertion or deletion breaks the balance factor rule. The four cases are LL, RR, LR, and RL.

Izquierda – Rotación izquierda

Esta rotación se realiza cuando se inserta un nuevo nodo en el hijo izquierdo del subárbol izquierdo.

Árbol AVL izquierda – Rotación izquierda

Árbol AVL izquierda – Rotación izquierda

A single right rotation is performed. This case fires when a node has BF +2 and its left child has BF +1.

Derecha – Rotación a la derecha

Esta rotación se realiza cuando se inserta un nuevo nodo en el hijo derecho del subárbol derecho.

Árbol AVL a la derecha – Rotación a la derecha

A single left rotation is performed. This case fires when a node has BF −2 and its right child has BF −1.

Rotación derecha – izquierda

Esta rotación se realiza cuando se inserta un nuevo nodo en el hijo izquierdo del subárbol derecho.

Árbol AVL derecha – rotación izquierda

Fires when BF(node) = −2 and BF(right-child) = +1. Right-rotate the right child, then left-rotate the node.

Rotación izquierda – derecha

Esta rotación se realiza cuando se inserta un nuevo nodo en el hijo derecho del subárbol izquierdo.

Árbol AVL izquierda – rotación derecha

Fires when BF(node) = +2 and BF(left-child) = −1. Left-rotate the left child, then right-rotate the node.

Inserción en árboles AVL

Insertion is almost identical to a plain BST insert. After every insert, the tree walks up and re-balances. Insert runs in O(log n) worst-case time.

Inserción en árboles AVL

Implementación de inserción de árbol AVL

Paso 1: Insert the node using the standard BST algorithm. In the example above, insert 160.

Paso 2: Update the balance factor of every ancestor along the insertion path.

Paso 3: If any ancestor violates the balance factor range, perform the matching rotation. In the example, node 350’s balance factor is violated, so an LL rotation restores balance.

  1. If BF(node) = +2 y BF(left-child) = +1, perform LL rotation.
  2. If BF(node) = −2 y BF(right-child) = −1, perform RR rotation.
  3. If BF(node) = −2 y BF(right-child) = +1, perform RL rotation.
  4. If BF(node) = +2 y BF(left-child) = −1, perform LR rotation.

ARTÍCULOS RELACIONADOS

Eliminación en árboles AVL

Deletion follows the same logic as a plain BST and re-balances afterwards.

Paso 1: Encuentra el elemento en el árbol.

Paso 2: Delete the node using standard BST deletion.

Paso 3: Two cases are possible.

Caso 1: Eliminando del subárbol derecho.

  • 1A. If BF(node) = +2 y BF(left-child) = +1, perform LL rotation.
  • 1B. If BF(node) = +2 y BF(left-child) = −1, perform LR rotation.
  • 1C. If BF(node) = +2 y BF(left-child) = 0, perform LL rotation.

Eliminación en árboles AVL

Caso 2: Deleting from the left subtree.

  • 2A. If BF(node) = −2 y BF(right-child) = −1, perform RR rotation.
  • 2B. If BF(node) = −2 y BF(right-child) = +1, perform RL rotation.
  • 2C. If BF(node) = −2 y BF(right-child) = 0, perform RR rotation.

Eliminación en árboles AVL

C++ Ejemplo de árboles AVL

A continuación se muestra un C++ program implementing AVL Trees:

#include <iostream>
#include <queue>
#include <unordered_map>
using namespace std;

struct node {
    struct node *left;
    int data;
    int height;
    struct node *right;
};

class AVL {
public:
    struct node *root;

    AVL() {
        this->root = NULL;
    }

    int calheight(struct node *p) {
        if (p->left && p->right) {
            if (p->left->height < p->right->height)
                return p->right->height + 1;
            else
                return p->left->height + 1;
        }
        else if (p->left && p->right == NULL) {
            return p->left->height + 1;
        }
        else if (p->left == NULL && p->right) {
            return p->right->height + 1;
        }
        return 0;
    }

    int bf(struct node *n) {
        if (n->left && n->right)
            return n->left->height - n->right->height;
        else if (n->left && n->right == NULL)
            return n->left->height;
        else if (n->left == NULL && n->right)
            return -n->right->height;
        return 0;
    }

    struct node *llrotation(struct node *n) {
        struct node *p = n;
        struct node *tp = p->left;
        p->left = tp->right;
        tp->right = p;
        return tp;
    }

    struct node *rrrotation(struct node *n) {
        struct node *p = n;
        struct node *tp = p->right;
        p->right = tp->left;
        tp->left = p;
        return tp;
    }

    struct node *rlrotation(struct node *n) {
        struct node *p = n;
        struct node *tp = p->right;
        struct node *tp2 = p->right->left;
        p->right = tp2->left;
        tp->left = tp2->right;
        tp2->left = p;
        tp2->right = tp;
        return tp2;
    }

    struct node *lrrotation(struct node *n) {
        struct node *p = n;
        struct node *tp = p->left;
        struct node *tp2 = p->left->right;
        p->left = tp2->right;
        tp->right = tp2->left;
        tp2->right = p;
        tp2->left = tp;
        return tp2;
    }

    struct node *insert(struct node *r, int data) {
        if (r == NULL) {
            r = new struct node;
            r->data = data;
            r->left = r->right = NULL;
            r->height = 1;
            return r;
        }
        if (data < r->data)
            r->left = insert(r->left, data);
        else
            r->right = insert(r->right, data);

        r->height = calheight(r);

        if (bf(r) == 2 && bf(r->left) == 1)       r = llrotation(r);
        else if (bf(r) == -2 && bf(r->right) == -1) r = rrrotation(r);
        else if (bf(r) == -2 && bf(r->right) == 1)  r = rlrotation(r);
        else if (bf(r) == 2 && bf(r->left) == -1)   r = lrrotation(r);

        return r;
    }

    void levelorder_newline() {
        if (this->root == NULL) {
            cout << "\nEmpty tree\n";
            return;
        }
        levelorder_newline(this->root);
    }

    void levelorder_newline(struct node *v) {
        queue<struct node *> q;
        struct node *cur;
        q.push(v);
        q.push(NULL);
        while (!q.empty()) {
            cur = q.front();
            q.pop();
            if (cur == NULL && q.size() != 0) {
                cout << "\n";
                q.push(NULL);
                continue;
            }
            if (cur != NULL) {
                cout << " " << cur->data;
                if (cur->left != NULL)  q.push(cur->left);
                if (cur->right != NULL) q.push(cur->right);
            }
        }
    }

    struct node *deleteNode(struct node *p, int data) {
        if (p->left == NULL && p->right == NULL) {
            if (p == this->root) this->root = NULL;
            delete p;
            return NULL;
        }
        struct node *q;
        if (p->data < data)      p->right = deleteNode(p->right, data);
        else if (p->data > data) p->left  = deleteNode(p->left, data);
        else {
            if (p->left != NULL) {
                q = inpre(p->left);
                p->data = q->data;
                p->left = deleteNode(p->left, q->data);
            } else {
                q = insuc(p->right);
                p->data = q->data;
                p->right = deleteNode(p->right, q->data);
            }
        }

        if (bf(p) == 2 && bf(p->left) == 1)         p = llrotation(p);
        else if (bf(p) == 2 && bf(p->left) == -1)    p = lrrotation(p);
        else if (bf(p) == 2 && bf(p->left) == 0)     p = llrotation(p);
        else if (bf(p) == -2 && bf(p->right) == -1)  p = rrrotation(p);
        else if (bf(p) == -2 && bf(p->right) == 1)   p = rlrotation(p);
        else if (bf(p) == -2 && bf(p->right) == 0)   p = rrrotation(p);

        return p;
    }

    struct node *inpre(struct node *p) {
        while (p->right != NULL) p = p->right;
        return p;
    }

    struct node *insuc(struct node *p) {
        while (p->left != NULL) p = p->left;
        return p;
    }

    ~AVL() {}
};

int main() {
    AVL b;
    int c, x;
    do {
        cout << "\n1.Display levelorder on newline";
        cout << "\n2.Insert";
        cout << "\n3.Delete\n";
        cout << "\n0.Exit\n";
        cout << "\nChoice: ";
        cin >> c;
        switch (c) {
        case 1: b.levelorder_newline(); break;
        case 2:
            cout << "\nEnter no. "; cin >> x;
            b.root = b.insert(b.root, x);
            break;
        case 3:
            cout << "\nWhat to delete? "; cin >> x;
            b.root = b.deleteNode(b.root, x);
            break;
        case 0: break;
        }
    } while (c != 0);
}

Running example of the code above:

  1. Copy the code above and save it in a file named avl.cpp.
  2. Compilar el código:
g++ avl.cpp -o run
  1. Ejecute el código.
./run

C++ Ejemplo de árboles AVL

Ventajas de los árboles AVL

  • The height of the AVL Tree is always balanced and never grows beyond log N.
  • Search is faster than a plain Binary Search Tree because the tree cannot degenerate.
  • Self-balancing is automatic — no rebuild step is required.
  • Deterministic performance suits real-time systems and in-memory indexes.

Preguntas Frecuentes

An AVL Tree is a self-balancing binary search tree where the balance factor of every node stays in {-1, 0, +1}. Rotations restore this invariant on every insert or delete, keeping search, insert, and delete at O(log n).

The balance factor of a node equals height(left subtree) minus height(right subtree). Values must lie in {-1, 0, +1}. A balance factor of +2 or -2 signals that an insertion or deletion has unbalanced that node and a rotation is required.

The four rotations are LL, RR, LR, and RL. LL uses a single right rotation, RR uses a single left rotation, and LR and RL are double rotations that combine one rotation on the child with an opposite rotation on the node.

Insertion follows the standard BST rule, then the tree walks back up updating heights. If any ancestor breaks the balance rule, one single or double rotation restores balance. At most one rotation per insert is ever needed.

AVL Trees are strictly balanced with a balance factor of at most one, giving faster lookups. Red-Black Trees allow looser balance, which makes insert and delete cheaper but search slightly slower. Databases prefer red-black for write-heavy loads.

AVL Trees power in-memory database indexes, filesystem metadata, priority queues, phonebook lookups, spell checkers, and any workload that needs deterministic O(log n) search plus in-order traversal for range queries.

Yes. AI systems use AVL Trees for symbol tables, ordered feature stores, k-d tree balancing, and nearest-neighbour lookups on structured data. They also underpin ranked retrieval indexes in intelligent search pipelines.

Yes. GitHub Copilot and similar AI assistants scaffold insert, delete, and rotation routines in C++, Java, o Python, and generate unit tests that verify the balance factor invariant on every operation.

Resumir este post con: