AVL stabla: rotacije, umetanje, brisanje sa C++ Primjer
โก Pametni saลพetak
AVL Trees are self-balancing binary search trees where the height difference between the left and right subtrees of every node stays within -1, 0, or +1, guaranteeing O(log n) search performance.

ล to su AVL stabla?
AVL stabla are binary search trees in which the height difference between the left and right subtree of every node is -1, 0, or +1. They are self-balancing BSTs that maintain logarithmic search time, named after inventors Adelson-Velsky and Landis (AVL).
Kako radi AVL stablo?
To understand why AVL Trees exist, look at what goes wrong with a plain Stablo binarnog pretraลพivanja. Consider these keys inserted in the given order:
Vizualizacija AVL stabla
The tree grows linearly when keys arrive in increasing order, degenerating search to O(n). That defeats the purpose of a BST โ only a balanced tree keeps search logarithmic. Now look at the same keys inserted in a different order.
Same keys, different insertion order produces a shallower shape, so every search runs in O(log n). AVL Trees enforce that shape by watching the height on every insertion and correcting imbalance without breaking BST ordering.
Faktor ravnoteลพe u AVL stablima
The balance factor (BF) tracks each nodeโs height so the tree can self-balance on the fly.
Svojstva faktora ravnoteลพe
Faktor ravnoteลพe AVL stablo
- The balance factor is the difference between the height of the left subtree and the height of the right subtree.
Balance factor(node) = height(node->left) โ height(node->right)- The only allowed values are โ1, 0, and +1.
- A value of โ1 means the right subtree contains one extra level โ the node is right-heavy.
- A value of +1 means the left subtree contains one extra level โ the node is left-heavy.
- A value of 0 means both sides have equal height โ the node is perfectly balanced.
AVL rotacije
Rotations run whenever an insertion or deletion breaks the balance factor rule. The four cases are LL, RR, LR, and RL.
Lijevo โ Lijeva rotacija
Ova rotacija se izvodi kada se novi ฤvor umetne u lijevo dijete lijevog podstabla.
AVL stablo lijevo โ rotacija lijevo
A single right rotation is performed. This case fires when a node has BF +2 and its left child has BF +1.
Desno โ Desna rotacija
Ova rotacija se izvodi kada se novi ฤvor umetne u desno dijete desnog podstabla.
A single left rotation is performed. This case fires when a node has BF โ2 and its right child has BF โ1.
Rotacija desno โ lijevo
Ova rotacija se izvodi kada se novi ฤvor umetne u lijevo dijete desnog podstabla.
Fires when BF(node) = โ2 and BF(right-child) = +1. Right-rotate the right child, then left-rotate the node.
Rotacija lijevo โ desno
Ova rotacija se izvodi kada se novi ฤvor umetne u desno dijete lijevog podstabla.
Fires when BF(node) = +2 and BF(left-child) = โ1. Left-rotate the left child, then right-rotate the node.
Umetanje u AVL stabla
Insertion is almost identical to a plain BST insert. After every insert, the tree walks up and re-balances. Insert runs in O(log n) worst-case time.
Implementacija umetanja AVL stabla
Korak 1: Insert the node using the standard BST algorithm. In the example above, insert 160.
Korak 2: Update the balance factor of every ancestor along the insertion path.
Korak 3: If any ancestor violates the balance factor range, perform the matching rotation. In the example, node 350โs balance factor is violated, so an LL rotation restores balance.
- If
BF(node) = +2iBF(left-child) = +1, perform LL rotation. - If
BF(node) = โ2iBF(right-child) = โ1, perform RR rotation. - If
BF(node) = โ2iBF(right-child) = +1, perform RL rotation. - If
BF(node) = +2iBF(left-child) = โ1, perform LR rotation.
Brisanje u AVL stablima
Deletion follows the same logic as a plain BST and re-balances afterwards.
Korak 1: Pronaฤite element u stablu.
Korak 2: Delete the node using standard BST deletion.
Korak 3: Two cases are possible.
Sluฤaj 1: Brisanje iz desnog podstabla.
- 1A. If
BF(node) = +2iBF(left-child) = +1, perform LL rotation. - 1B. If
BF(node) = +2iBF(left-child) = โ1, perform LR rotation. - 1C. If
BF(node) = +2iBF(left-child) = 0, perform LL rotation.
Sluฤaj 2: Deleting from the left subtree.
- 2A. If
BF(node) = โ2iBF(right-child) = โ1, perform RR rotation. - 2B. If
BF(node) = โ2iBF(right-child) = +1, perform RL rotation. - 2C. If
BF(node) = โ2iBF(right-child) = 0, perform RR rotation.
C++ Primjer AVL stabala
Ispod je a C++ program implementing AVL Trees:
#include <iostream> #include <queue> #include <unordered_map> using namespace std; struct node { struct node *left; int data; int height; struct node *right; }; class AVL { public: struct node *root; AVL() { this->root = NULL; } int calheight(struct node *p) { if (p->left && p->right) { if (p->left->height < p->right->height) return p->right->height + 1; else return p->left->height + 1; } else if (p->left && p->right == NULL) { return p->left->height + 1; } else if (p->left == NULL && p->right) { return p->right->height + 1; } return 0; } int bf(struct node *n) { if (n->left && n->right) return n->left->height - n->right->height; else if (n->left && n->right == NULL) return n->left->height; else if (n->left == NULL && n->right) return -n->right->height; return 0; } struct node *llrotation(struct node *n) { struct node *p = n; struct node *tp = p->left; p->left = tp->right; tp->right = p; return tp; } struct node *rrrotation(struct node *n) { struct node *p = n; struct node *tp = p->right; p->right = tp->left; tp->left = p; return tp; } struct node *rlrotation(struct node *n) { struct node *p = n; struct node *tp = p->right; struct node *tp2 = p->right->left; p->right = tp2->left; tp->left = tp2->right; tp2->left = p; tp2->right = tp; return tp2; } struct node *lrrotation(struct node *n) { struct node *p = n; struct node *tp = p->left; struct node *tp2 = p->left->right; p->left = tp2->right; tp->right = tp2->left; tp2->right = p; tp2->left = tp; return tp2; } struct node *insert(struct node *r, int data) { if (r == NULL) { r = new struct node; r->data = data; r->left = r->right = NULL; r->height = 1; return r; } if (data < r->data) r->left = insert(r->left, data); else r->right = insert(r->right, data); r->height = calheight(r); if (bf(r) == 2 && bf(r->left) == 1) r = llrotation(r); else if (bf(r) == -2 && bf(r->right) == -1) r = rrrotation(r); else if (bf(r) == -2 && bf(r->right) == 1) r = rlrotation(r); else if (bf(r) == 2 && bf(r->left) == -1) r = lrrotation(r); return r; } void levelorder_newline() { if (this->root == NULL) { cout << "\nEmpty tree\n"; return; } levelorder_newline(this->root); } void levelorder_newline(struct node *v) { queue<struct node *> q; struct node *cur; q.push(v); q.push(NULL); while (!q.empty()) { cur = q.front(); q.pop(); if (cur == NULL && q.size() != 0) { cout << "\n"; q.push(NULL); continue; } if (cur != NULL) { cout << " " << cur->data; if (cur->left != NULL) q.push(cur->left); if (cur->right != NULL) q.push(cur->right); } } } struct node *deleteNode(struct node *p, int data) { if (p->left == NULL && p->right == NULL) { if (p == this->root) this->root = NULL; delete p; return NULL; } struct node *q; if (p->data < data) p->right = deleteNode(p->right, data); else if (p->data > data) p->left = deleteNode(p->left, data); else { if (p->left != NULL) { q = inpre(p->left); p->data = q->data; p->left = deleteNode(p->left, q->data); } else { q = insuc(p->right); p->data = q->data; p->right = deleteNode(p->right, q->data); } } if (bf(p) == 2 && bf(p->left) == 1) p = llrotation(p); else if (bf(p) == 2 && bf(p->left) == -1) p = lrrotation(p); else if (bf(p) == 2 && bf(p->left) == 0) p = llrotation(p); else if (bf(p) == -2 && bf(p->right) == -1) p = rrrotation(p); else if (bf(p) == -2 && bf(p->right) == 1) p = rlrotation(p); else if (bf(p) == -2 && bf(p->right) == 0) p = rrrotation(p); return p; } struct node *inpre(struct node *p) { while (p->right != NULL) p = p->right; return p; } struct node *insuc(struct node *p) { while (p->left != NULL) p = p->left; return p; } ~AVL() {} }; int main() { AVL b; int c, x; do { cout << "\n1.Display levelorder on newline"; cout << "\n2.Insert"; cout << "\n3.Delete\n"; cout << "\n0.Exit\n"; cout << "\nChoice: "; cin >> c; switch (c) { case 1: b.levelorder_newline(); break; case 2: cout << "\nEnter no. "; cin >> x; b.root = b.insert(b.root, x); break; case 3: cout << "\nWhat to delete? "; cin >> x; b.root = b.deleteNode(b.root, x); break; case 0: break; } } while (c != 0); }
Running example of the code above:
- Copy the code above and save it in a file named
avl.cpp. - Sastavite kod:
g++ avl.cpp -o run
- Pokrenite kod.
./run
Prednosti AVL stabala
- The height of the AVL Tree is always balanced and never grows beyond log N.
- Search is faster than a plain Binary Search Tree because the tree cannot degenerate.
- Self-balancing is automatic โ no rebuild step is required.
- Deterministic performance suits real-time systems and in-memory indexes.











