C言語で3×3マジックスクエアパズルを解く方法 Python

Begin
    Declare an array of size n*n
    Initialize the array to 0
    Set row = n/2
    Set column = n-1
    For all number i: from 1 to n*n
        If the row = -1 and column = n
            row = 0
            column = n-2
        Else
            If row = -1
                row = n-1
            If column = n
                column = 0
        If the position already contains a number
            decrement column by 2
            increment row by 1
            continue until the position is not 0
        Else
            put the number i into the calculated position
            increment i
        Increment column value
        Decrement row value
End

/*
A C/C++ program for generating odd order magic squares
*/
#include <bits/stdc++.h>
using namespace std;

void GenerateMagicSquare(int n)
{
    int magic[n][n];
    //initializing the array
    for(int i=0; i<n; i++)
        for(int j=0; j<n; j++)
            magic[i][j] = 0;
    //setting row and column value
    int i = n / 2;
    int j = n - 1;
    for (int k = 1; k <= n * n;)
    {
        //checking condition (c)
        if (i == -1 && j == n)
        {
            j = n - 2;
            i = 0;
        }
        else
        {
            //checking condition (a)
            if (j == n)
                j = 0;
            if (i < 0)
                i = n - 1;
        }
        //checking condition (b)
        if (magic[i][j])
        {
            j -= 2;
            i++;
            continue;
        }
        else
        {
            //placing the number into the array
            magic[i][j] = k;
            k++;
        }
        //for the next number setting (i-1, j+1)
        j++;
        i--;
    }
    //printing the matrix
    for (int i = 0; i < n; i++)
    {
        for (int j = 0; j < n; j++)
            cout << magic[i][j] << "  ";
        cout << endl;
    }
}
int main()
{
    //This code works for only odd numbers
    int n = 7;
    cout<<"The magic sum is " << n*(n*n+1)/2 <<endl;
    GenerateMagicSquare(n);
    return 0;
}

The magic sum is 175

20  12  4  45  37  29  28
11  3  44  36  35  27  19
2  43  42  34  26  18  10
49  41  33  25  17  9  1
40  32  24  16  8  7  48
31  23  15  14  6  47  39
22  21  13  5  46  38  30

def GenerateMagicSquare(n):
    #initializing the array
    magic = [[0 for x in range(n)]
                for y in range(n)]
    #setting row and column value
    i = n // 2
    j = n - 1
    k = 1
    while k <= (n * n):
        #checking condition (c)
        if i == -1 and j == n:
            j = n - 2
            i = 0
        else:
            #checking condition (a)
            if j == n:
                j = 0
            if i < 0:
                i = n - 1
        #checking conditon (b)
        if magic[i][j]:
            j = j - 2
            i = i + 1
            continue
        else:
            #placing the number into the array
            magic[i][j] = k
            k = k + 1
        #for the next number setting (i-1, j+1)
        j = j + 1
        i = i - 1
    #printing the matrix
    for i in range(0, n):
        for j in range(0, n):
            print('%2d ' % (magic[i][j]),end='')
            if j == n - 1:
                print()
#This code works for only odd numbers
n = 7
print("The magic sum is ",n * (n * n + 1) // 2, "\n")
GenerateMagicSquare(n)

The magic sum is  175

20 12  4 45 37 29 28
11  3 44 36 35 27 19
 2 43 42 34 26 18 10
49 41 33 25 17  9  1
40 32 24 16  8  7 48
31 23 15 14  6 47 39
22 21 13  5 46 38 30